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api.ajax({
url : api.getPrefs({ sync: true,key: 'ip'})+'/rest/app/elderMealAction!foodImages.action',
// url:'http://116.193.50.232:8080/KLJYTEST/rest/app/elderMealAction!foodImages.action',
method: 'post',
headers : {
userId : $api.getStorage('userId'),
token : $api.getStorage('token'),
},
data: {
values: { currentPageNo: 0,
pageSize:20,
restaurantId:"1"},
}
}, function(ret, err) {
//alert(JSON.stringify(ret));
if (ret) {
if ('1' == ret.status) {
var response = ret.response;
// response = response.reverse();
//alert(JSON.stringify( ret ));
var str = "";
var imgSrc = "";
var foodname ="";
$(response).each(function(index, ele){
//imgSrc = ele.pic;
foodname = ele.mc;
imgSrc =(ele.pic ==""?"../../image/caidan"+(index+2)+".jpg"api.getPrefs({sync : true,key : 'ip'}))+"/"+ele.pic);
str += "<li><div><img src='"+imgSrc+"' /><label>"+foodname+"</label></div></li>";
});
$(".ulmenu-two").html(str);
}else{
// alert(ret.status)
errorResponseCheck('../', ret);
}
}else {
alert("error");
}
});
这段代码是网络请求返回999时候我想进入登录界面 errorResponseCheck这方法会进入 但是如果我把方法上的alert去掉就不会进入放出来就会进入登录界面。。。。
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