IOS的api.openTabLayout无法传递pageParam到下一个stml页面

BIP336772

机型：iphone6s plus

版本：ios12.5.7
问题描述：使用api.openTabLayout跳转到avm页面时，pageParam没有被传递过去（在stml中获取api.pageParam取到的值是一个空的对象）。以下是openTabLayout的参数

1. {"name":"common_voucherDetail3897849","url":"widget://pages/common/voucherDetail.stml","title":"使用普惠券","pageParam":"3897849","hideNavigationBar":false,"hideTabBar":true,"avm":true,"navigationBar":{"shadow":"#999","color":"#FFF","background":"#114aa3","leftButtons":{"iconPath":"widget://images/back/back.png"}}}

复制代码

经过测试，安卓手机可以正常传递pageParam

技术咨询-Kenny

pageParam是JSON对象类型，按照文档来